0.636

π=3.141592653589793238462643383279502884197169399375105820 9749445923078164062862089986280348253421170679821480865132 8230664709384460955058223172535940812848111745028410270193 8521105559644622948954930381964428810975665933446128475648 2337867831652712019091456485669234603486104543266482133936 0726024914127372458700660631558817488152092096282925409171 5364367892590360011330530548820466521384146951941511609…

2/π=0.63661977236758

This is the factor to figure out the DC value of a full wave:fullwave
 
If the peak voltage is 100 volts, the DC voltage of the full wave is 63.66 volts. To charge a 6V battery, you can use 6.366V DC supply. Then all you needed is a AC source with 10V peak voltage and rectify it to get the 6.36 DC supply.

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